32x-4=4x2+60

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Solution for 32x-4=4x2+60 equation: 



32x-4=4x^2+60

We move all terms to the left:

32x-4-(4x^2+60)=0

We get rid of parentheses

-4x^2+32x-60-4=0

We add all the numbers together, and all the variables

-4x^2+32x-64=0

a = -4; b = 32; c = -64;
Δ = b2-4ac
Δ = 322-4·(-4)·(-64)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-32}{-8}=+4$

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