(1/2)10x=25

Solution for (1/2)10x=25 equation:

(1/2)10x=25

We move all terms to the left:

(1/2)10x-(25)=0


Domain of the equation: 2)10x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)10x-25=0

We multiply parentheses

10x^2-25=0

a = 10; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·10·(-25)
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{10}}{2*10}=\frac{0-10\sqrt{10}}{20}
=-\frac{10\sqrt{10}}{20}
=-\frac{\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{10}}{2*10}=\frac{0+10\sqrt{10}}{20}
=\frac{10\sqrt{10}}{20}
=\frac{\sqrt{10}}{2}
$