4(x+2)2+5=149

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Solution for 4(x+2)2+5=149 equation: 



4(x+2)2+5=149

We move all terms to the left:

4(x+2)2+5-(149)=0

We add all the numbers together, and all the variables

4(x+2)2-144=0

We multiply parentheses

8x+16-144=0

We add all the numbers together, and all the variables

8x-128=0

We move all terms containing x to the left, all other terms to the right

8x=128

x=128/8

x=16

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