If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x=5x(x+2)
We move all terms to the left:
x-(5x(x+2))=0
We calculate terms in parentheses: -(5x(x+2)), so:We get rid of parentheses
5x(x+2)
We multiply parentheses
5x^2+10x
Back to the equation:
-(5x^2+10x)
-5x^2+x-10x=0
We add all the numbers together, and all the variables
-5x^2-9x=0
a = -5; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-5)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-5}=\frac{0}{-10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-5}=\frac{18}{-10} =-1+4/5 $
| 4×x-15=65 | | 1n+11=2n+9 | | 3g-5=-6g+19 | | 5.7=9.3-0.4x | | j/3-21=-16 | | -x-3+2x=2 | | 12.5+5x=16-2x | | -5(2-w)=20 | | 6(2x+1)+3=-3(-5x-3)-3x | | 4x+3x-1x=-36 | | (4x-25)+(3x-12)=180 | | x=10x² | | 1=v3+7 | | 62=9m+8 | | v/3+7=5 | | 12-10x=57 | | -2f-6=-f | | 12-4x=-4x+12 | | X+13+13+14x=131 | | (3x-4)(x^2+3x-4)=0 | | 15p-19p+12p-2p+5=-1 | | h-243=1192 | | 4x+1=1÷ | | x-3+5x=0.75(8x+28) | | y=-4*4+9 | | 15=k/8 | | 10x-25=15x-35 | | 24=12-4b | | 2y–4=20 | | -5(x-1)=5+-5x | | 2(w+5)=7w+4 | | 5(1y+4)-3y=4y+12 |