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6(2x+1)+3=-3(-5x-3)-3x
We move all terms to the left:
6(2x+1)+3-(-3(-5x-3)-3x)=0
We multiply parentheses
12x-(-3(-5x-3)-3x)+6+3=0
We calculate terms in parentheses: -(-3(-5x-3)-3x), so:We add all the numbers together, and all the variables
-3(-5x-3)-3x
We add all the numbers together, and all the variables
-3x-3(-5x-3)
We multiply parentheses
-3x+15x+9
We add all the numbers together, and all the variables
12x+9
Back to the equation:
-(12x+9)
12x-(12x+9)+9=0
We get rid of parentheses
12x-12x-9+9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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