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x=2x(5x+2)
We move all terms to the left:
x-(2x(5x+2))=0
We calculate terms in parentheses: -(2x(5x+2)), so:We get rid of parentheses
2x(5x+2)
We multiply parentheses
10x^2+4x
Back to the equation:
-(10x^2+4x)
-10x^2+x-4x=0
We add all the numbers together, and all the variables
-10x^2-3x=0
a = -10; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-10)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-10}=\frac{6}{-20} =-3/10 $
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