(7y+11)(9y+16)=0

Solution for (7y+11)(9y+16)=0 equation:

(7y+11)(9y+16)=0

We multiply parentheses ..

(+63y^2+112y+99y+176)=0

We get rid of parentheses

63y^2+112y+99y+176=0

We add all the numbers together, and all the variables

63y^2+211y+176=0

a = 63; b = 211; c = +176;
Δ = b2-4ac
Δ = 2112-4·63·176
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(211)-13}{2*63}=\frac{-224}{126}
=-1+7/9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(211)+13}{2*63}=\frac{-198}{126}
=-1+4/7
$