x=2.2x(1-x)

Solution for x=2.2x(1-x) equation:

x=2.2x(1-x)

We move all terms to the left:

x-(2.2x(1-x))=0

We add all the numbers together, and all the variables

x-(2.2x(-1x+1))=0


We calculate terms in parentheses: -(2.2x(-1x+1)), so:

2.2x(-1x+1)

We multiply parentheses

-2x^2+2x

Back to the equation:

-(-2x^2+2x)


We get rid of parentheses

2x^2-2x+x=0

We add all the numbers together, and all the variables

2x^2-1x=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$