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1/2x+1/2x+x+x=540
We move all terms to the left:
1/2x+1/2x+x+x-(540)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+1/2x+1/2x-540=0
We multiply all the terms by the denominator
2x*2x-540*2x+1+1=0
We add all the numbers together, and all the variables
2x*2x-540*2x+2=0
Wy multiply elements
4x^2-1080x+2=0
a = 4; b = -1080; c = +2;
Δ = b2-4ac
Δ = -10802-4·4·2
Δ = 1166368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1166368}=\sqrt{16*72898}=\sqrt{16}*\sqrt{72898}=4\sqrt{72898}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1080)-4\sqrt{72898}}{2*4}=\frac{1080-4\sqrt{72898}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1080)+4\sqrt{72898}}{2*4}=\frac{1080+4\sqrt{72898}}{8} $
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