x=10(2x)-8(2x+1)

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Solution for x=10(2x)-8(2x+1) equation: 



x=10(2x)-8(2x+1)

We move all terms to the left:

x-(10(2x)-8(2x+1))=0



We calculate terms in parentheses: -(102x-8(2x+1)), so:

102x-8(2x+1)

We multiply parentheses

102x-16x-8

We add all the numbers together, and all the variables

86x-8

Back to the equation:

-(86x-8)



We get rid of parentheses

x-86x+8=0

We add all the numbers together, and all the variables

-85x+8=0

We move all terms containing x to the left, all other terms to the right

-85x=-8

x=-8/-85

x=8/85

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