7y-9+3(2y+5)=-2(y+6)

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Solution for 7y-9+3(2y+5)=-2(y+6) equation: 



7y-9+3(2y+5)=-2(y+6)

We move all terms to the left:

7y-9+3(2y+5)-(-2(y+6))=0

We multiply parentheses

7y+6y-(-2(y+6))+15-9=0



We calculate terms in parentheses: -(-2(y+6)), so:

-2(y+6)

We multiply parentheses

-2y-12

Back to the equation:

-(-2y-12)



We add all the numbers together, and all the variables

13y-(-2y-12)+6=0

We get rid of parentheses

13y+2y+12+6=0

We add all the numbers together, and all the variables

15y+18=0

We move all terms containing y to the left, all other terms to the right

15y=-18

y=-18/15

y=-1+1/5

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