x=1/3(3x)=0

Solution for x=1/3(3x)=0 equation:

x=1/3(3x)=0

We move all terms to the left:

x-(1/3(3x))=0


Domain of the equation: 33x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-(+1/33x)=0

We get rid of parentheses

x-1/33x=0

We multiply all the terms by the denominator


x*33x-1=0

Wy multiply elements

33x^2-1=0

a = 33; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·33·(-1)
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{33}}{2*33}=\frac{0-2\sqrt{33}}{66}
=-\frac{2\sqrt{33}}{66}
=-\frac{\sqrt{33}}{33}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{33}}{2*33}=\frac{0+2\sqrt{33}}{66}
=\frac{2\sqrt{33}}{66}
=\frac{\sqrt{33}}{33}
$