2(f+2)=3(f-4)

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Solution for 2(f+2)=3(f-4) equation: 



2(f+2)=3(f-4)

We move all terms to the left:

2(f+2)-(3(f-4))=0

We multiply parentheses

2f-(3(f-4))+4=0



We calculate terms in parentheses: -(3(f-4)), so:

3(f-4)

We multiply parentheses

3f-12

Back to the equation:

-(3f-12)



We get rid of parentheses

2f-3f+12+4=0

We add all the numbers together, and all the variables

-1f+16=0

We move all terms containing f to the left, all other terms to the right

-f=-16

f=-16/-1

f=+16

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