2x-2=3(x-1)-5(6-2x)-2

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Solution for 2x-2=3(x-1)-5(6-2x)-2 equation: 



2x-2=3(x-1)-5(6-2x)-2

We move all terms to the left:

2x-2-(3(x-1)-5(6-2x)-2)=0

We add all the numbers together, and all the variables

2x-(3(x-1)-5(-2x+6)-2)-2=0



We calculate terms in parentheses: -(3(x-1)-5(-2x+6)-2), so:

3(x-1)-5(-2x+6)-2

We multiply parentheses

3x+10x-3-30-2

We add all the numbers together, and all the variables

13x-35

Back to the equation:

-(13x-35)



We get rid of parentheses

2x-13x+35-2=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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