x=(2x+4)(6x+12)

Solution for x=(2x+4)(6x+12) equation:

x=(2x+4)(6x+12)

We move all terms to the left:

x-((2x+4)(6x+12))=0

We multiply parentheses ..

-((+12x^2+24x+24x+48))+x=0


We calculate terms in parentheses: -((+12x^2+24x+24x+48)), so:

(+12x^2+24x+24x+48)

We get rid of parentheses

12x^2+24x+24x+48

We add all the numbers together, and all the variables

12x^2+48x+48

Back to the equation:

-(12x^2+48x+48)


We add all the numbers together, and all the variables

x-(12x^2+48x+48)=0

We get rid of parentheses

-12x^2+x-48x-48=0

We add all the numbers together, and all the variables

-12x^2-47x-48=0

a = -12; b = -47; c = -48;
Δ = b2-4ac
Δ = -472-4·(-12)·(-48)
Δ = -95
Delta is less than zero, so there is no solution for the equation