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5-(x-3)=(2+x)-5
We move all terms to the left:
5-(x-3)-((2+x)-5)=0
We add all the numbers together, and all the variables
-(x-3)-((x+2)-5)+5=0
We get rid of parentheses
-x-((x+2)-5)+3+5=0
We calculate terms in parentheses: -((x+2)-5), so:We add all the numbers together, and all the variables
(x+2)-5
We get rid of parentheses
x+2-5
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
-1x-(x-3)+8=0
We get rid of parentheses
-1x-x+3+8=0
We add all the numbers together, and all the variables
-2x+11=0
We move all terms containing x to the left, all other terms to the right
-2x=-11
x=-11/-2
x=5+1/2
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