x=(0.2+(2*0.2)+(2*0.2)+(3*04))/4

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Solution for x=(0.2+(2*0.2)+(2*0.2)+(3*04))/4 equation:



x=(0.2+(2*0.2)+(2*0.2)+(3*04))/4
We move all terms to the left:
x-((0.2+(2*0.2)+(2*0.2)+(3*04))/4)=0
We add all the numbers together, and all the variables
x-((0.2+(0.4)+(0.4)+12)/4)=0
We multiply all the terms by the denominator
x*4)-((0.2+(0.4)+(0.4)+12)=0
Wy multiply elements
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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