If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2+24x-4=0
a = 9; b = 24; c = -4;
Δ = b2-4ac
Δ = 242-4·9·(-4)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{5}}{2*9}=\frac{-24-12\sqrt{5}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{5}}{2*9}=\frac{-24+12\sqrt{5}}{18} $
| (8x+2)+(70+60)=180 | | 4x+6=10x-6 | | 8x=(360/9)² | | 1.73x=x+10 | | -2=3x^2-7x | | 3x^2/9=3 | | x-8/3=x-3/8 | | 6−4x=7 | | 4n-9=2n+9 | | 3–4b=15 | | x-(-16)=22+13 | | 5x+3=17(-)2x | | 4^x+4=2^x+2 | | x^2+4x-8+10-4x=0 | | 11b=46+98 | | 3^2x=45 | | X^2-4x-254=0 | | 10x-x(-10)=3x+52 | | X^2-5x-254=0 | | 8m-3×5m+6m+2=0 | | X^2-5x-255=0 | | 2x-12=66 | | 5(k+11)+(2k-3)-7=2(k-4) | | 5(k+55)+(2k-3)-7=2(k-4) | | X(x-27)-18x=(x-3)(x+16 | | 1+x/100=10000 | | 9x=16-x^ | | 6+-5=2x+3 | | k=4/5+1/4 | | x2-10x-4000=0 | | 3m-12=2m+3 | | 3b=15=30 |