5(k+55)+(2k-3)-7=2(k-4)

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Solution for 5(k+55)+(2k-3)-7=2(k-4) equation: 



5(k+55)+(2k-3)-7=2(k-4)

We move all terms to the left:

5(k+55)+(2k-3)-7-(2(k-4))=0

We multiply parentheses

5k+(2k-3)-(2(k-4))+275-7=0

We get rid of parentheses

5k+2k-(2(k-4))-3+275-7=0



We calculate terms in parentheses: -(2(k-4)), so:

2(k-4)

We multiply parentheses

2k-8

Back to the equation:

-(2k-8)



We add all the numbers together, and all the variables

7k-(2k-8)+265=0

We get rid of parentheses

7k-2k+8+265=0

We add all the numbers together, and all the variables

5k+273=0

We move all terms containing k to the left, all other terms to the right

5k=-273

k=-273/5

k=-54+3/5

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