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x3+x2+x+1=(x+1)3
We move all terms to the left:
x3+x2+x+1-((x+1)3)=0
We add all the numbers together, and all the variables
x^3+x^2+x-((x+1)3)+1=0
We calculate terms in parentheses: -((x+1)3), so:We do not support expression: x^3
(x+1)3
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
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