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3(3x+5)=20-7(3+x)
We move all terms to the left:
3(3x+5)-(20-7(3+x))=0
We add all the numbers together, and all the variables
3(3x+5)-(20-7(x+3))=0
We multiply parentheses
9x-(20-7(x+3))+15=0
We calculate terms in parentheses: -(20-7(x+3)), so:We get rid of parentheses
20-7(x+3)
determiningTheFunctionDomain -7(x+3)+20
We multiply parentheses
-7x-21+20
We add all the numbers together, and all the variables
-7x-1
Back to the equation:
-(-7x-1)
9x+7x+1+15=0
We add all the numbers together, and all the variables
16x+16=0
We move all terms containing x to the left, all other terms to the right
16x=-16
x=-16/16
x=-1
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