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2/5-7=12/5h-2h+3
We move all terms to the left:
2/5-7-(12/5h-2h+3)=0
Domain of the equation: 5h-2h+3)!=0We add all the numbers together, and all the variables
h∈R
-(-2h+12/5h+3)-7+2/5=0
We get rid of parentheses
2h-12/5h-3-7+2/5=0
We calculate fractions
2h-3-7=0
We add all the numbers together, and all the variables
2h-10=0
We move all terms containing h to the left, all other terms to the right
2h=10
h=10/2
h=5
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