x3+4x2-11x-30=(x+2)(x-3)(x+5)=0

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Solution for x3+4x2-11x-30=(x+2)(x-3)(x+5)=0 equation: 



x3+4x^2-11x-30=(x+2)(x-3)(x+5)=0

We move all terms to the left:

x3+4x^2-11x-30-((x+2)(x-3)(x+5))=0

We add all the numbers together, and all the variables

4x^2+x^3-11x-((x+2)(x-3)(x+5))-30=0

We multiply parentheses ..

4x^2+x^3-((+x^2-3x+2x-6)(x+5))-11x-30=0



We calculate terms in parentheses: -((+x^2-3x+2x-6)(x+5)), so:

(+x^2-3x+2x-6)(x+5)



We do not support expression: x^3

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