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x2=5(x+100)
We move all terms to the left:
x2-(5(x+100))=0
We add all the numbers together, and all the variables
x^2-(5(x+100))=0
We calculate terms in parentheses: -(5(x+100)), so:We get rid of parentheses
5(x+100)
We multiply parentheses
5x+500
Back to the equation:
-(5x+500)
x^2-5x-500=0
a = 1; b = -5; c = -500;
Δ = b2-4ac
Δ = -52-4·1·(-500)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-45}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+45}{2*1}=\frac{50}{2} =25 $
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