1/8(5y+64)=1/2(20+2y)

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Solution for 1/8(5y+64)=1/2(20+2y) equation: 



1/8(5y+64)=1/2(20+2y)

We move all terms to the left:

1/8(5y+64)-(1/2(20+2y))=0



Domain of the equation: 8(5y+64)!=0

y∈R





Domain of the equation: 2(20+2y))!=0

y∈R



We add all the numbers together, and all the variables

1/8(5y+64)-(1/2(2y+20))=0

We calculate fractions


(2y2/(8(5y+64)*2(2y+20)))+(-8y5/(8(5y+64)*2(2y+20)))=0



We calculate terms in parentheses: +(2y2/(8(5y+64)*2(2y+20))), so:

2y2/(8(5y+64)*2(2y+20))

We multiply all the terms by the denominator


2y2

We add all the numbers together, and all the variables

2y^2

Back to the equation:

+(2y^2)





We calculate terms in parentheses: +(-8y5/(8(5y+64)*2(2y+20))), so:

-8y5/(8(5y+64)*2(2y+20))

We multiply all the terms by the denominator


-8y5

We add all the numbers together, and all the variables

-8y^5

We do not support eypression: y^5

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