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x2=49529
We move all terms to the left:
x2-(49529)=0
We add all the numbers together, and all the variables
x^2-49529=0
a = 1; b = 0; c = -49529;
Δ = b2-4ac
Δ = 02-4·1·(-49529)
Δ = 198116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{198116}=\sqrt{4*49529}=\sqrt{4}*\sqrt{49529}=2\sqrt{49529}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{49529}}{2*1}=\frac{0-2\sqrt{49529}}{2} =-\frac{2\sqrt{49529}}{2} =-\sqrt{49529} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{49529}}{2*1}=\frac{0+2\sqrt{49529}}{2} =\frac{2\sqrt{49529}}{2} =\sqrt{49529} $
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