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11(y2+5)=330
We move all terms to the left:
11(y2+5)-(330)=0
We add all the numbers together, and all the variables
11(+y^2+5)-330=0
We multiply parentheses
11y^2+55-330=0
We add all the numbers together, and all the variables
11y^2-275=0
a = 11; b = 0; c = -275;
Δ = b2-4ac
Δ = 02-4·11·(-275)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*11}=\frac{-110}{22} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*11}=\frac{110}{22} =5 $
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