x2=2x-48=0

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Solution for x2=2x-48=0 equation: 



x2=2x-48=0

We move all terms to the left:

x2-(2x-48)=0

We add all the numbers together, and all the variables

x^2-(2x-48)=0

We get rid of parentheses

x^2-2x+48=0

a = 1; b = -2; c = +48;
Δ = b2-4ac
Δ = -22-4·1·48
Δ = -188
Delta is less than zero, so there is no solution for the equation

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