6x-8-7x-4=4(1+4x)+2(x-8)

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Solution for 6x-8-7x-4=4(1+4x)+2(x-8) equation: 



6x-8-7x-4=4(1+4x)+2(x-8)

We move all terms to the left:

6x-8-7x-4-(4(1+4x)+2(x-8))=0

We add all the numbers together, and all the variables

6x-7x-(4(4x+1)+2(x-8))-8-4=0

We add all the numbers together, and all the variables

-1x-(4(4x+1)+2(x-8))-12=0



We calculate terms in parentheses: -(4(4x+1)+2(x-8)), so:

4(4x+1)+2(x-8)

We multiply parentheses

16x+2x+4-16

We add all the numbers together, and all the variables

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

-1x-18x+12-12=0

We add all the numbers together, and all the variables

-19x=0

x=0/-19

x=0

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