x2=26x+27

Solution for x2=26x+27 equation:

x2=26x+27

We move all terms to the left:

x2-(26x+27)=0

We add all the numbers together, and all the variables

x^2-(26x+27)=0

We get rid of parentheses

x^2-26x-27=0

a = 1; b = -26; c = -27;
Δ = b2-4ac
Δ = -262-4·1·(-27)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-28}{2*1}=\frac{-2}{2}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+28}{2*1}=\frac{54}{2}
=27
$