1/7(6-3x)=3

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Solution for 1/7(6-3x)=3 equation: 



1/7(6-3x)=3

We move all terms to the left:

1/7(6-3x)-(3)=0



Domain of the equation: 7(6-3x)!=0

x∈R



We add all the numbers together, and all the variables

1/7(-3x+6)-3=0

We multiply all the terms by the denominator


-3*7(-3x+6)+1=0

Wy multiply elements

-21x(-+1=0

We use the square of the difference formula

-21x(-1=0

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