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x2-72x+80=0
We add all the numbers together, and all the variables
x^2-72x+80=0
a = 1; b = -72; c = +80;
Δ = b2-4ac
Δ = -722-4·1·80
Δ = 4864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4864}=\sqrt{256*19}=\sqrt{256}*\sqrt{19}=16\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-16\sqrt{19}}{2*1}=\frac{72-16\sqrt{19}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+16\sqrt{19}}{2*1}=\frac{72+16\sqrt{19}}{2} $
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