2m-m-12=2(m-4)+m

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Solution for 2m-m-12=2(m-4)+m equation: 



2m-m-12=2(m-4)+m

We move all terms to the left:

2m-m-12-(2(m-4)+m)=0

We add all the numbers together, and all the variables

m-(2(m-4)+m)-12=0



We calculate terms in parentheses: -(2(m-4)+m), so:

2(m-4)+m

We add all the numbers together, and all the variables

m+2(m-4)

We multiply parentheses

m+2m-8

We add all the numbers together, and all the variables

3m-8

Back to the equation:

-(3m-8)



We get rid of parentheses

m-3m+8-12=0

We add all the numbers together, and all the variables

-2m-4=0

We move all terms containing m to the left, all other terms to the right

-2m=4

m=4/-2

m=-2

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