3(y+4)+y=2(y+4)-5

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Solution for 3(y+4)+y=2(y+4)-5 equation: 



3(y+4)+y=2(y+4)-5

We move all terms to the left:

3(y+4)+y-(2(y+4)-5)=0

We add all the numbers together, and all the variables

y+3(y+4)-(2(y+4)-5)=0

We multiply parentheses

y+3y-(2(y+4)-5)+12=0



We calculate terms in parentheses: -(2(y+4)-5), so:

2(y+4)-5

We multiply parentheses

2y+8-5

We add all the numbers together, and all the variables

2y+3

Back to the equation:

-(2y+3)



We add all the numbers together, and all the variables

4y-(2y+3)+12=0

We get rid of parentheses

4y-2y-3+12=0

We add all the numbers together, and all the variables

2y+9=0

We move all terms containing y to the left, all other terms to the right

2y=-9

y=-9/2

y=-4+1/2

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