x2-50x+300=0

Solution for x2-50x+300=0 equation:

x2-50x+300=0

We add all the numbers together, and all the variables

x^2-50x+300=0

a = 1; b = -50; c = +300;
Δ = b2-4ac
Δ = -502-4·1·300
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{13}}{2*1}=\frac{50-10\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{13}}{2*1}=\frac{50+10\sqrt{13}}{2}
$