5(4y-3)=-21(3-y)

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Solution for 5(4y-3)=-21(3-y) equation: 



5(4y-3)=-21(3-y)

We move all terms to the left:

5(4y-3)-(-21(3-y))=0

We add all the numbers together, and all the variables

5(4y-3)-(-21(-1y+3))=0

We multiply parentheses

20y-(-21(-1y+3))-15=0



We calculate terms in parentheses: -(-21(-1y+3)), so:

-21(-1y+3)

We multiply parentheses

21y-63

Back to the equation:

-(21y-63)



We get rid of parentheses

20y-21y+63-15=0

We add all the numbers together, and all the variables

-1y+48=0

We move all terms containing y to the left, all other terms to the right

-y=-48

y=-48/-1

y=+48

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