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x2-34x+225=0
We add all the numbers together, and all the variables
x^2-34x+225=0
a = 1; b = -34; c = +225;
Δ = b2-4ac
Δ = -342-4·1·225
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-16}{2*1}=\frac{18}{2} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+16}{2*1}=\frac{50}{2} =25 $
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