3(y-6)-4=-5(-3y+8)-4Y

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Solution for 3(y-6)-4=-5(-3y+8)-4Y equation: 



3(y-6)-4=-5(-3y+8)-4

We move all terms to the left:

3(y-6)-4-(-5(-3y+8)-4)=0

We multiply parentheses

3y-(-5(-3y+8)-4)-18-4=0



We calculate terms in parentheses: -(-5(-3y+8)-4), so:

-5(-3y+8)-4

We multiply parentheses

15y-40-4

We add all the numbers together, and all the variables

15y-44

Back to the equation:

-(15y-44)



We add all the numbers together, and all the variables

3y-(15y-44)-22=0

We get rid of parentheses

3y-15y+44-22=0

We add all the numbers together, and all the variables

-12y+22=0

We move all terms containing y to the left, all other terms to the right

-12y=-22

y=-22/-12

y=1+5/6

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