13(-3v+1)=7(-2v-2)

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Solution for 13(-3v+1)=7(-2v-2) equation: 



13(-3v+1)=7(-2v-2)

We move all terms to the left:

13(-3v+1)-(7(-2v-2))=0

We multiply parentheses

-39v-(7(-2v-2))+13=0



We calculate terms in parentheses: -(7(-2v-2)), so:

7(-2v-2)

We multiply parentheses

-14v-14

Back to the equation:

-(-14v-14)



We get rid of parentheses

-39v+14v+14+13=0

We add all the numbers together, and all the variables

-25v+27=0

We move all terms containing v to the left, all other terms to the right

-25v=-27

v=-27/-25

v=1+2/25

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