20(x+2)+31=4(5x+10)+31

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Solution for 20(x+2)+31=4(5x+10)+31 equation: 



20(x+2)+31=4(5x+10)+31

We move all terms to the left:

20(x+2)+31-(4(5x+10)+31)=0

We multiply parentheses

20x-(4(5x+10)+31)+40+31=0



We calculate terms in parentheses: -(4(5x+10)+31), so:

4(5x+10)+31

We multiply parentheses

20x+40+31

We add all the numbers together, and all the variables

20x+71

Back to the equation:

-(20x+71)



We add all the numbers together, and all the variables

20x-(20x+71)+71=0

We get rid of parentheses

20x-20x-71+71=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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