x2-30x+96=-10x

Solution for x2-30x+96=-10x equation:

x2-30x+96=-10x

We move all terms to the left:

x2-30x+96-(-10x)=0

We add all the numbers together, and all the variables

x^2-30x-(-10x)+96=0

We get rid of parentheses

x^2-30x+10x+96=0

We add all the numbers together, and all the variables

x^2-20x+96=0

a = 1; b = -20; c = +96;
Δ = b2-4ac
Δ = -202-4·1·96
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*1}=\frac{16}{2}
=8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*1}=\frac{24}{2}
=12
$