-4(4x-5)=39+3x

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Solution for -4(4x-5)=39+3x equation: 



-4(4x-5)=39+3x

We move all terms to the left:

-4(4x-5)-(39+3x)=0

We add all the numbers together, and all the variables

-4(4x-5)-(3x+39)=0

We multiply parentheses

-16x-(3x+39)+20=0

We get rid of parentheses

-16x-3x-39+20=0

We add all the numbers together, and all the variables

-19x-19=0

We move all terms containing x to the left, all other terms to the right

-19x=19

x=19/-19

x=-1

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