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X2-2=6X-5
We move all terms to the left:
X2-2-(6X-5)=0
We add all the numbers together, and all the variables
X^2-(6X-5)-2=0
We get rid of parentheses
X^2-6X+5-2=0
We add all the numbers together, and all the variables
X^2-6X+3=0
a = 1; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·1·3
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{6}}{2*1}=\frac{6-2\sqrt{6}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{6}}{2*1}=\frac{6+2\sqrt{6}}{2} $
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