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1/a+1/5a=3
We move all terms to the left:
1/a+1/5a-(3)=0
Domain of the equation: a!=0
a∈R
Domain of the equation: 5a!=0We calculate fractions
a!=0/5
a!=0
a∈R
5a/5a^2+a/5a^2-3=0
We multiply all the terms by the denominator
5a+a-3*5a^2=0
We add all the numbers together, and all the variables
6a-3*5a^2=0
Wy multiply elements
-15a^2+6a=0
a = -15; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-15)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-15}=\frac{-12}{-30} =2/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-15}=\frac{0}{-30} =0 $
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