x2-23x+72=0

Solution for x2-23x+72=0 equation:

x2-23x+72=0

We add all the numbers together, and all the variables

x^2-23x+72=0

a = 1; b = -23; c = +72;
Δ = b2-4ac
Δ = -232-4·1·72
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{241}}{2*1}=\frac{23-\sqrt{241}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{241}}{2*1}=\frac{23+\sqrt{241}}{2}
$