20(5x+1)+6(3x-13)=15(5x-1)

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Solution for 20(5x+1)+6(3x-13)=15(5x-1) equation: 



20(5x+1)+6(3x-13)=15(5x-1)

We move all terms to the left:

20(5x+1)+6(3x-13)-(15(5x-1))=0

We multiply parentheses

100x+18x-(15(5x-1))+20-78=0



We calculate terms in parentheses: -(15(5x-1)), so:

15(5x-1)

We multiply parentheses

75x-15

Back to the equation:

-(75x-15)



We add all the numbers together, and all the variables

118x-(75x-15)-58=0

We get rid of parentheses

118x-75x+15-58=0

We add all the numbers together, and all the variables

43x-43=0

We move all terms containing x to the left, all other terms to the right

43x=43

x=43/43

x=1

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