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6x^2-3x=3(7x^2-4x
We move all terms to the left:
6x^2-3x-(3(7x^2-4x)=0
We calculate terms in parentheses: -(3(7x^2-4x), so:
3(7x^2-4x
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3(7x^2-4x
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| 6x+7=-51-7x | | l/5=20 | | 2x-3/3x+1=15/39 | | 〖3x〗^2-10x+8=0 | | 100x=23.67 | | 2(2l+7)=18 | | 3(x2-2)+18=0 | | 25−73x+26+39x=x+97−81x+41+17x | | 3(x2-2+18=0 | | 4x-(16/x-3)=0 | | 2l=20 | | 3(2t-3)=15 | | 4(x+8)=6(x+5) | | 4a-a+3=3a+3 | | 9x+12=6x14 | | 3x+1/5=-4 | | 4x–13=17+8x | | (9-2x)/5=9 | | 10h-24=76h= | | 0=(1)(-0.82)+b | | 9-x)/2=11 | | (x-6)/(7)+8=-1 | | 5(3s+7)=155 | | (x+2)/(9)-4=0 | | 3*(x-1)-4=2*(x-1) | | 15=(2x-3) | | 6x2+15x+41=0 | | 4-4m=4-4m | | =4−3b+2.5=4 | | 4x(x-2)-2x(2x-1)-4=0 | | 7-x/12=0 | | 3x^2-700x+20000=0 |