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x2-20x-69=0
We add all the numbers together, and all the variables
x^2-20x-69=0
a = 1; b = -20; c = -69;
Δ = b2-4ac
Δ = -202-4·1·(-69)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-26}{2*1}=\frac{-6}{2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+26}{2*1}=\frac{46}{2} =23 $
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