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2(x+5)+3(2x+2)=2+2(3x+1)
We move all terms to the left:
2(x+5)+3(2x+2)-(2+2(3x+1))=0
We multiply parentheses
2x+6x-(2+2(3x+1))+10+6=0
We calculate terms in parentheses: -(2+2(3x+1)), so:We add all the numbers together, and all the variables
2+2(3x+1)
determiningTheFunctionDomain 2(3x+1)+2
We multiply parentheses
6x+2+2
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
8x-(6x+4)+16=0
We get rid of parentheses
8x-6x-4+16=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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