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x2-20x+38=9x+8
We move all terms to the left:
x2-20x+38-(9x+8)=0
We add all the numbers together, and all the variables
x^2-20x-(9x+8)+38=0
We get rid of parentheses
x^2-20x-9x-8+38=0
We add all the numbers together, and all the variables
x^2-29x+30=0
a = 1; b = -29; c = +30;
Δ = b2-4ac
Δ = -292-4·1·30
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{721}}{2*1}=\frac{29-\sqrt{721}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{721}}{2*1}=\frac{29+\sqrt{721}}{2} $
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